ref: 0bd1a8057841386754f9f4a8a268616c7ce80e80
dir: /hat.c/
/*
* Code to generate patches of the aperiodic 'hat' tiling discovered
* in 2023.
*
* auxiliary/doc/hats.html contains an explanation of the basic ideas
* of this algorithm, which can't really be put in a source file
* because it just has too many complicated diagrams. So read that
* first, because the comments in here will refer to it.
*
* Discoverers' website: https://cs.uwaterloo.ca/~csk/hat/
* Preprint of paper: https://arxiv.org/abs/2303.10798
*/
#include <assert.h>
#include <math.h>
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "puzzles.h"
#include "hat.h"
/*
* Coordinate system:
*
* The output of this code lives on the tiling known to grid.c as
* 'Kites', which can be viewed as a tiling of hexagons each of which
* is subdivided into six kites sharing their pointy vertex, or
* (equivalently) a tiling of equilateral triangles each subdivided
* into three kits sharing their blunt vertex.
*
* We express coordinates in this system relative to the basis (1, r)
* where r = (1 + sqrt(3)i) / 2 is a primitive 6th root of unity. This
* gives us a system in which two integer coordinates can address any
* grid point, provided we scale up so that the side length of the
* equilateral triangles in the tiling is 6.
*/
typedef struct Point {
int x, y; /* represents x + yr */
} Point;
static inline Point pointscale(int scale, Point a)
{
Point r = { scale * a.x, scale * a.y };
return r;
}
static inline Point pointadd(Point a, Point b)
{
Point r = { a.x + b.x, a.y + b.y };
return r;
}
/*
* We identify a single kite by the coordinates of its four vertices.
* This allows us to construct the coordinates of an adjacent kite by
* taking affine transformations of the original kite's vertices.
*
* This is a useful way to do it because it means that if you reflect
* the kite (by swapping its left and right vertices) then these
* transformations also perform in a reflected way. This will be
* useful in the code below that outputs the coordinates of each hat,
* because this way it can work by walking around its 8 kites using a
* fixed set of steps, and if the hat is reflected, then we just
* reflect the starting kite before doing that, and everything still
* works.
*/
typedef struct Kite {
Point centre, left, right, outer;
} Kite;
static inline Kite kite_left(Kite k)
{
Kite r;
r.centre = k.centre;
r.right = k.left;
r.outer = pointadd(pointscale(2, k.left), pointscale(-1, k.outer));
r.left = pointadd(pointadd(k.centre, k.left), pointscale(-1, k.right));
return r;
}
static inline Kite kite_right(Kite k)
{
Kite r;
r.centre = k.centre;
r.left = k.right;
r.outer = pointadd(pointscale(2, k.right), pointscale(-1, k.outer));
r.right = pointadd(pointadd(k.centre, k.right), pointscale(-1, k.left));
return r;
}
static inline Kite kite_forward_left(Kite k)
{
Kite r;
r.outer = k.outer;
r.right = k.left;
r.centre = pointadd(pointscale(2, k.left), pointscale(-1, k.centre));
r.left = pointadd(pointadd(k.right, k.left), pointscale(-1, k.centre));
return r;
}
static inline Kite kite_forward_right(Kite k)
{
Kite r;
r.outer = k.outer;
r.left = k.right;
r.centre = pointadd(pointscale(2, k.right), pointscale(-1, k.centre));
r.right = pointadd(pointadd(k.left, k.right), pointscale(-1, k.centre));
return r;
}
typedef enum KiteStep { KS_LEFT, KS_RIGHT, KS_F_LEFT, KS_F_RIGHT } KiteStep;
static inline Kite kite_step(Kite k, KiteStep step)
{
switch (step) {
case KS_LEFT: return kite_left(k);
case KS_RIGHT: return kite_right(k);
case KS_F_LEFT: return kite_forward_left(k);
default /* case KS_F_RIGHT */: return kite_forward_right(k);
}
}
/*
* Function to enumerate the kites in a rectangular region, in a
* serpentine-raster fashion so that every kite delivered shares an
* edge with a recent previous one.
*/
#define KE_NKEEP 3
typedef struct KiteEnum {
/* Fields private to the enumerator */
int state;
int x, y, w, h;
unsigned curr_index;
/* Fields the client can legitimately read out */
Kite *curr;
Kite recent[KE_NKEEP];
unsigned last_index;
KiteStep last_step; /* step that got curr from recent[last_index] */
} KiteEnum;
static void first_kite(KiteEnum *s, int w, int h)
{
Kite start = { {0,0}, {0, 3}, {3, 0}, {2, 2} };
size_t i;
for (i = 0; i < KE_NKEEP; i++)
s->recent[i] = start; /* initialise to *something* */
s->curr_index = 0;
s->curr = &s->recent[s->curr_index];
s->state = 1;
s->w = w;
s->h = h;
s->x = 0;
s->y = 0;
}
static bool next_kite(KiteEnum *s)
{
unsigned lastbut1 = s->last_index;
s->last_index = s->curr_index;
s->curr_index = (s->curr_index + 1) % KE_NKEEP;
s->curr = &s->recent[s->curr_index];
switch (s->state) {
/* States 1,2,3 walk rightwards along the upper side of a
* horizontal grid line with a pointy kite end at the start
* point */
case 1:
s->last_step = KS_F_RIGHT;
s->state = 2;
break;
case 2:
if (s->x+1 >= s->w) {
s->last_step = KS_F_RIGHT;
s->state = 4;
break;
}
s->last_step = KS_RIGHT;
s->state = 3;
s->x++;
break;
case 3:
s->last_step = KS_RIGHT;
s->state = 1;
break;
/* State 4 is special: we've just moved up into a row below a
* grid line, but we can't produce the rightmost tile of that
* row because it's not adjacent any tile so far emitted. So
* instead, emit the second-rightmost tile, and next time,
* we'll emit the rightmost. */
case 4:
s->last_step = KS_LEFT;
s->state = 5;
break;
/* And now we have to emit the third-rightmost tile relative
* to the last but one tile we emitted (the one from state 2,
* not state 4). */
case 5:
s->last_step = KS_RIGHT;
s->last_index = lastbut1;
s->state = 6;
break;
/* Now states 6-8 handle the general case of walking leftwards
* along the lower side of a line, starting from a
* right-angled kite end. */
case 6:
if (s->x <= 0) {
if (s->y+1 >= s->h) {
s->state = 0;
return false;
}
s->last_step = KS_RIGHT;
s->state = 9;
s->y++;
break;
}
s->last_step = KS_F_RIGHT;
s->state = 7;
s->x--;
break;
case 7:
s->last_step = KS_RIGHT;
s->state = 8;
break;
case 8:
s->last_step = KS_RIGHT;
s->state = 6;
break;
/* States 9,10,11 walk rightwards along the upper side of a
* horizontal grid line with a right-angled kite end at the
* start point. This time there's no awkward transition from
* the previous row. */
case 9:
s->last_step = KS_RIGHT;
s->state = 10;
break;
case 10:
s->last_step = KS_RIGHT;
s->state = 11;
break;
case 11:
if (s->x+1 >= s->w) {
/* Another awkward transition to the next row, where we
* have to generate it based on the previous state-9 tile.
* But this time at least we generate the rightmost tile
* of the new row, so the next states will be simple. */
s->last_step = KS_F_RIGHT;
s->last_index = lastbut1;
s->state = 12;
break;
}
s->last_step = KS_F_RIGHT;
s->state = 9;
s->x++;
break;
/* States 12,13,14 walk leftwards along the upper edge of a
* horizontal grid line with a pointy kite end at the start
* point */
case 12:
s->last_step = KS_F_RIGHT;
s->state = 13;
break;
case 13:
if (s->x <= 0) {
if (s->y+1 >= s->h) {
s->state = 0;
return false;
}
s->last_step = KS_LEFT;
s->state = 1;
s->y++;
break;
}
s->last_step = KS_RIGHT;
s->state = 14;
s->x--;
break;
case 14:
s->last_step = KS_RIGHT;
s->state = 12;
break;
default:
return false;
}
*s->curr = kite_step(s->recent[s->last_index], s->last_step);
return true;
}
/*
* Assorted useful definitions.
*/
typedef enum TileType { TT_H, TT_T, TT_P, TT_F, TT_KITE, TT_HAT } TileType;
static const char tilechars[] = "HTPF";
#define HAT_KITES 8 /* number of kites in a hat */
#define MT_MAXEXPAND 13 /* largest number of metatiles in any expansion */
/*
* Definitions for the autogenerated hat-tables.h header file that
* defines all the lookup tables.
*/
typedef struct KitemapEntry {
int kite, hat, meta; /* all -1 if impossible */
} KitemapEntry;
typedef struct MetamapEntry {
int meta, meta2;
} MetamapEntry;
static inline size_t kitemap_index(KiteStep step, unsigned kite,
unsigned hat, unsigned meta)
{
return step + 4 * (kite + 8 * (hat + 4 * meta));
}
static inline size_t metamap_index(unsigned meta, unsigned meta2)
{
return meta2 * MT_MAXEXPAND + meta;
}
/*
* The actual tables.
*/
#include "hat-tables.h"
/*
* One set of tables that we write by hand: the permitted ways to
* extend the coordinate system outwards from a given metatile.
*
* One obvious approach would be to make a table of all the places
* each metatile can appear in the expansion of another (e.g. H can be
* subtile 0, 1 or 2 of another H, subtile 0 of a T, or 0 or 1 of a P
* or an F), and when we need to decide what our current topmost tile
* turns out to be a subtile of, choose equiprobably at random from
* those options.
*
* That's what I did originally, but a better approach is to skew the
* probabilities. We'd like to generate our patch of actual tiling
* uniformly at random, in the sense that if you selected uniformly
* from a very large region of the plane, the distribution of possible
* finite patches of tiling would converge to some limit as that
* region tended to infinity, and we'd be picking from that limiting
* distribution on finite patches.
*
* For this we have to refer back to the original paper, which
* indicates the subset of each metatile's expansion that can be
* considered to 'belong' to that metatile, such that every subtile
* belongs to exactly one parent metatile, and the overlaps are
* eliminated. Reading out the diagrams from their Figure 2.8:
*
* - H: we discard three of the outer F subtiles, in the symmetric
* positions index by our coordinates as 7, 10, 11. So we keep the
* remaining subtiles {0,1,2,3,4,5,6,8,9,12}, which consist of
* three H, one T, three P and three F.
*
* - T: only the central H expanded from a T is considered to belong
* to it, so we just keep {0}, a single H.
*
* - P: we discard everything intersected by a long edge of the
* parallelogram, leaving the central three tiles and the endmost
* pair of F. That is, we keep {0,1,4,5,10}, consisting of two H,
* one P and two F.
*
* - F: looks like P at one end, and we retain the corresponding set
* of tiles there, but at the other end we keep the two F on either
* side of the endmost one. So we keep {0,1,3,6,8,10}, consisting of
* two H, one P and _three_ F.
*
* Adding up the tile numbers gives us this matrix system:
*
* (H_1) (3 1 2 2)(H_0)
* (T_1) = (1 0 0 0)(T_0)
* (P_1) (3 0 1 1)(P_0)
* (F_1) (3 0 2 3)(F_0)
*
* which says that if you have a patch of metatiling consisting of H_0
* H tiles, T_0 T tiles etc, then this matrix shows the number H_1 of
* smaller H tiles, etc, expanded from it.
*
* If you expand _many_ times, that's equivalent to raising the matrix
* to a power:
*
* n
* (H_n) (3 1 2 2) (H_0)
* (T_n) = (1 0 0 0) (T_0)
* (P_n) (3 0 1 1) (P_0)
* (F_n) (3 0 2 3) (F_0)
*
* The limiting distribution of metatiles is obtained by looking at
* the four-way ratio between H_n, T_n, P_n and F_n as n tends to
* infinity. To calculate this, we find the eigenvalues and
* eigenvectors of the matrix, and extract the eigenvector
* corresponding to the eigenvalue of largest magnitude. (Things get
* more complicated in cases where there isn't a _unique_ eigenvalue
* of largest magnitude, but here, there is.)
*
* That eigenvector is
*
* [ 1 ] [ 1 ]
* [ (7 - 3 sqrt(5)) / 2 ] ~= [ 0.14589803375031545538 ]
* [ 3 sqrt(5) - 6 ] [ 0.70820393249936908922 ]
* [ (9 - 3 sqrt(5)) / 2 ] [ 1.14589803375031545538 ]
*
* So those are the limiting relative proportions of metatiles.
*
* So if we have a particular metatile, how likely is it for its
* parent to be one of those? We have to adjust by the number of
* metatiles of each type that each tile has as its children. For
* example, the P and F tiles have one P child each, but the H has
* three P children. So if we have a P, the proportion of H in its
* potential ancestry is three times what's shown here. (And T can't
* occur at all as a parent.)
*
* In other words, we should choose _each coordinate_ with probability
* corresponding to one of those numbers (scaled down so they all sum
* to 1). Continuing to use P as an example, it will be:
*
* - child 4 of H with relative probability 1
* - child 5 of H with relative probability 1
* - child 6 of H with relative probability 1
* - child 4 of P with relative probability 0.70820393249936908922
* - child 3 of F with relative probability 1.14589803375031545538
*
* and then we obtain the true probabilities by scaling those values
* down so that they sum to 1.
*
* The tables below give a reasonable approximation in 32-bit
* integers to these proportions.
*/
typedef struct MetatilePossibleParent {
TileType type;
unsigned index;
unsigned long probability;
} MetatilePossibleParent;
/* The above probabilities scaled up by 10000000 */
#define PROB_H 10000000
#define PROB_T 1458980
#define PROB_P 7082039
#define PROB_F 11458980
static const MetatilePossibleParent parents_H[] = {
{ TT_H, 0, PROB_H },
{ TT_H, 1, PROB_H },
{ TT_H, 2, PROB_H },
{ TT_T, 0, PROB_T },
{ TT_P, 0, PROB_P },
{ TT_P, 1, PROB_P },
{ TT_F, 0, PROB_F },
{ TT_F, 1, PROB_F },
};
static const MetatilePossibleParent parents_T[] = {
{ TT_H, 3, PROB_H },
};
static const MetatilePossibleParent parents_P[] = {
{ TT_H, 4, PROB_H },
{ TT_H, 5, PROB_H },
{ TT_H, 6, PROB_H },
{ TT_P, 4, PROB_P },
{ TT_F, 3, PROB_F },
};
static const MetatilePossibleParent parents_F[] = {
{ TT_H, 8, PROB_H },
{ TT_H, 9, PROB_H },
{ TT_H, 12, PROB_H },
{ TT_P, 5, PROB_P },
{ TT_P, 10, PROB_P },
{ TT_F, 6, PROB_F },
{ TT_F, 8, PROB_F },
{ TT_F, 10, PROB_F },
};
static const MetatilePossibleParent *const possible_parents[] = {
parents_H, parents_T, parents_P, parents_F,
};
static const size_t n_possible_parents[] = {
lenof(parents_H), lenof(parents_T), lenof(parents_P), lenof(parents_F),
};
/*
* Similarly, we also want to choose our absolute starting hat with
* close to uniform probability, which again we do by looking at the
* limiting ratio of the metatile types, and this time, scaling by the
* number of hats in each metatile.
*
* We cheatingly use the same MetatilePossibleParent struct, because
* it's got all the right fields, even if it has an inappropriate
* name.
*/
static const MetatilePossibleParent starting_hats[] = {
{ TT_H, 0, PROB_H },
{ TT_H, 1, PROB_H },
{ TT_H, 2, PROB_H },
{ TT_H, 3, PROB_H },
{ TT_T, 0, PROB_P },
{ TT_P, 0, PROB_P },
{ TT_P, 1, PROB_P },
{ TT_F, 0, PROB_F },
{ TT_F, 1, PROB_F },
};
#undef PROB_H
#undef PROB_T
#undef PROB_P
#undef PROB_F
/*
* Coordinate system for tracking kites within a randomly selected
* part of the recursively expanded hat tiling.
*
* HatCoords will store an array of HatCoord, in little-endian
* arrangement. So hc->c[0] will always have type TT_KITE and index a
* single kite within a hat; hc->c[1] will have type TT_HAT and index
* a hat within a first-order metatile; hc->c[2] will be the smallest
* metatile containing this hat, and hc->c[3, 4, 5, ...] will be
* higher-order metatiles as needed.
*
* The last coordinate stored, hc->c[hc->nc-1], will have a tile type
* but no index (represented by index==-1). This means "we haven't
* decided yet what this level of metatile needs to be". If we need to
* refer to this level during the step_coords algorithm, we make it up
* at random, based on a table of what metatiles each type can
* possibly be part of, at what index.
*/
typedef struct HatCoord {
int index; /* index within that tile, or -1 if not yet known */
TileType type; /* type of this tile */
} HatCoord;
typedef struct HatCoords {
HatCoord *c;
size_t nc, csize;
} HatCoords;
static HatCoords *hc_new(void)
{
HatCoords *hc = snew(HatCoords);
hc->nc = hc->csize = 0;
hc->c = NULL;
return hc;
}
static void hc_free(HatCoords *hc)
{
if (hc) {
sfree(hc->c);
sfree(hc);
}
}
static void hc_make_space(HatCoords *hc, size_t size)
{
if (hc->csize < size) {
hc->csize = hc->csize * 5 / 4 + 16;
if (hc->csize < size)
hc->csize = size;
hc->c = sresize(hc->c, hc->csize, HatCoord);
}
}
static HatCoords *hc_copy(HatCoords *hc_in)
{
HatCoords *hc_out = hc_new();
hc_make_space(hc_out, hc_in->nc);
memcpy(hc_out->c, hc_in->c, hc_in->nc * sizeof(*hc_out->c));
hc_out->nc = hc_in->nc;
return hc_out;
}
static const MetatilePossibleParent *choose_mpp(
random_state *rs, const MetatilePossibleParent *parents, size_t nparents)
{
/*
* If we needed to do this _efficiently_, we'd rewrite all those
* tables above as cumulative frequency tables and use binary
* search. But this happens about log n times in a grid of area n,
* so it hardly matters, and it's easier to keep the tables
* legible.
*/
unsigned long limit = 0, value;
size_t i;
for (i = 0; i < nparents; i++)
limit += parents[i].probability;
value = random_upto(rs, limit);
for (i = 0; i+1 < nparents; i++) {
if (value < parents[i].probability)
return &parents[i];
value -= parents[i].probability;
}
assert(i == nparents - 1);
assert(value < parents[i].probability);
return &parents[i];
}
/*
* HatCoordContext is the shared context of a whole run of the
* algorithm. Its 'prototype' HatCoords object represents the
* coordinates of the starting kite, and is extended as necessary; any
* other HatCoord that needs extending will copy the higher-order
* values from ctx->prototype as needed, so that once each choice has
* been made, it remains consistent.
*
* When we're inventing a random piece of tiling in the first place,
* we append to ctx->prototype by choosing a random (but legal)
* higher-level metatile for the current topmost one to turn out to be
* part of. When we're replaying a generation whose parameters are
* already stored, we don't have a random_state, and we make fixed
* decisions if not enough coordinates were provided.
*
* (Of course another approach would be to reject grid descriptions
* that didn't define enough coordinates! But that would involve a
* whole extra iteration over the whole grid region just for
* validation, and that seems like more timewasting than really
* needed. So we tolerate short descriptions, and do something
* deterministic with them.)
*/
typedef struct HatCoordContext {
random_state *rs;
HatCoords *prototype;
} HatCoordContext;
static void init_coords_random(HatCoordContext *ctx, random_state *rs)
{
const MetatilePossibleParent *starting_hat = choose_mpp(
rs, starting_hats, lenof(starting_hats));
ctx->rs = rs;
ctx->prototype = hc_new();
hc_make_space(ctx->prototype, 3);
ctx->prototype->c[2].type = starting_hat->type;
ctx->prototype->c[2].index = -1;
ctx->prototype->c[1].type = TT_HAT;
ctx->prototype->c[1].index = starting_hat->index;
ctx->prototype->c[0].type = TT_KITE;
ctx->prototype->c[0].index = random_upto(rs, HAT_KITES);
ctx->prototype->nc = 3;
}
static inline int metatile_char_to_enum(char metatile)
{
return (metatile == 'H' ? TT_H :
metatile == 'T' ? TT_T :
metatile == 'P' ? TT_P :
metatile == 'F' ? TT_F : -1);
}
static void init_coords_params(HatCoordContext *ctx,
const struct HatPatchParams *hp)
{
size_t i;
ctx->rs = NULL;
ctx->prototype = hc_new();
assert(hp->ncoords >= 3);
hc_make_space(ctx->prototype, hp->ncoords + 1);
ctx->prototype->nc = hp->ncoords + 1;
for (i = 0; i < hp->ncoords; i++)
ctx->prototype->c[i].index = hp->coords[i];
ctx->prototype->c[hp->ncoords].type =
metatile_char_to_enum(hp->final_metatile);
ctx->prototype->c[hp->ncoords].index = -1;
ctx->prototype->c[0].type = TT_KITE;
ctx->prototype->c[1].type = TT_HAT;
for (i = hp->ncoords - 1; i > 1; i--) {
TileType metatile = ctx->prototype->c[i+1].type;
assert(hp->coords[i] < nchildren[metatile]);
ctx->prototype->c[i].type = children[metatile][hp->coords[i]];
}
assert(hp->coords[0] < 8);
}
static HatCoords *initial_coords(HatCoordContext *ctx)
{
return hc_copy(ctx->prototype);
}
/*
* Extend hc until it has at least n coordinates in, by copying from
* ctx->prototype if needed, and extending ctx->prototype if needed in
* order to do that.
*/
static void ensure_coords(HatCoordContext *ctx, HatCoords *hc, size_t n)
{
if (ctx->prototype->nc < n) {
hc_make_space(ctx->prototype, n);
while (ctx->prototype->nc < n) {
TileType type = ctx->prototype->c[ctx->prototype->nc - 1].type;
assert(ctx->prototype->c[ctx->prototype->nc - 1].index == -1);
const MetatilePossibleParent *parent;
if (ctx->rs)
parent = choose_mpp(ctx->rs, possible_parents[type],
n_possible_parents[type]);
else
parent = possible_parents[type];
ctx->prototype->c[ctx->prototype->nc - 1].index = parent->index;
ctx->prototype->c[ctx->prototype->nc].index = -1;
ctx->prototype->c[ctx->prototype->nc].type = parent->type;
ctx->prototype->nc++;
}
}
hc_make_space(hc, n);
while (hc->nc < n) {
assert(hc->c[hc->nc - 1].index == -1);
assert(hc->c[hc->nc - 1].type == ctx->prototype->c[hc->nc - 1].type);
hc->c[hc->nc - 1].index = ctx->prototype->c[hc->nc - 1].index;
hc->c[hc->nc].index = -1;
hc->c[hc->nc].type = ctx->prototype->c[hc->nc].type;
hc->nc++;
}
}
static void cleanup_coords(HatCoordContext *ctx)
{
hc_free(ctx->prototype);
}
#ifdef DEBUG_COORDS
static inline void debug_coords(const char *prefix, HatCoords *hc,
const char *suffix)
{
const char *sep = "";
static const char *const types[] = {"H","T","P","F","kite","hat"};
fputs(prefix, stderr);
for (size_t i = 0; i < hc->nc; i++) {
fprintf(stderr, "%s %s ", sep, types[hc->c[i].type]);
sep = " .";
if (hc->c[i].index == -1)
fputs("?", stderr);
else
fprintf(stderr, "%d", hc->c[i].index);
}
fputs(suffix, stderr);
}
#else
#define debug_coords(p,c,s) ((void)0)
#endif
/*
* The actual system for finding the coordinates of an adjacent kite.
*/
/*
* Kitemap step: ensure we have enough coordinates to know two levels
* of meta-tiling, and use the kite map for the outer layer to move
* around the individual kites. If this fails, return NULL.
*/
static HatCoords *try_step_coords_kitemap(
HatCoordContext *ctx, HatCoords *hc_in, KiteStep step)
{
ensure_coords(ctx, hc_in, 4);
debug_coords(" try kitemap ", hc_in, "\n");
unsigned kite = hc_in->c[0].index;
unsigned hat = hc_in->c[1].index;
unsigned meta = hc_in->c[2].index;
TileType meta2type = hc_in->c[3].type;
const KitemapEntry *ke = &kitemap[meta2type][
kitemap_index(step, kite, hat, meta)];
if (ke->kite >= 0) {
/*
* Success! We've got coordinates for the next kite in this
* direction.
*/
HatCoords *hc_out = hc_copy(hc_in);
hc_out->c[2].index = ke->meta;
hc_out->c[2].type = children[meta2type][ke->meta];
hc_out->c[1].index = ke->hat;
hc_out->c[1].type = TT_HAT;
hc_out->c[0].index = ke->kite;
hc_out->c[0].type = TT_KITE;
debug_coords(" success! ", hc_out, "\n");
return hc_out;
}
return NULL;
}
/*
* Recursive metamap step. Try using the metamap to rewrite the
* coordinates at hc->c[depth] and hc->c[depth+1] (using the metamap
* for the tile type described in hc->c[depth+2]). If successful,
* recurse back down to see if this led to a successful step via the
* kitemap. If even that fails (so that we need to try a higher-order
* metamap rewrite), return NULL.
*/
static HatCoords *try_step_coords_metamap(
HatCoordContext *ctx, HatCoords *hc_in, KiteStep step, size_t depth)
{
HatCoords *hc_tmp = NULL, *hc_out;
ensure_coords(ctx, hc_in, depth+3);
#ifdef DEBUG_COORDS
fprintf(stderr, " try meta %-4d", (int)depth);
debug_coords("", hc_in, "\n");
#endif
unsigned meta_orig = hc_in->c[depth].index;
unsigned meta2_orig = hc_in->c[depth+1].index;
TileType meta3type = hc_in->c[depth+2].type;
unsigned meta = meta_orig, meta2 = meta2_orig;
while (true) {
const MetamapEntry *me;
HatCoords *hc_curr = hc_tmp ? hc_tmp : hc_in;
if (depth > 2)
hc_out = try_step_coords_metamap(ctx, hc_curr, step, depth - 1);
else
hc_out = try_step_coords_kitemap(ctx, hc_curr, step);
if (hc_out) {
hc_free(hc_tmp);
return hc_out;
}
me = &metamap[meta3type][metamap_index(meta, meta2)];
assert(me->meta != -1);
if (me->meta == meta_orig && me->meta2 == meta2_orig) {
hc_free(hc_tmp);
return NULL;
}
meta = me->meta;
meta2 = me->meta2;
/*
* We must do the rewrite in a copy of hc_in. It's not
* _necessarily_ obvious that that's the case (any successful
* rewrite leaves the coordinates still valid and still
* referring to the same kite, right?). But the problem is
* that we might do a rewrite at this level more than once,
* and in between, a metamap rewrite at the next level down
* might have modified _one_ of the two coordinates we're
* messing about with. So it's easiest to let the recursion
* just use a separate copy.
*/
if (!hc_tmp)
hc_tmp = hc_copy(hc_in);
hc_tmp->c[depth+1].index = meta2;
hc_tmp->c[depth+1].type = children[meta3type][meta2];
hc_tmp->c[depth].index = meta;
hc_tmp->c[depth].type = children[hc_tmp->c[depth+1].type][meta];
debug_coords(" rewritten -> ", hc_tmp, "\n");
}
}
/*
* The top-level algorithm for finding the next tile.
*/
static HatCoords *step_coords(HatCoordContext *ctx, HatCoords *hc_in,
KiteStep step)
{
HatCoords *hc_out;
size_t depth;
#ifdef DEBUG_COORDS
static const char *const directions[] = {
" left\n", " right\n", " forward left\n", " forward right\n" };
debug_coords("step start ", hc_in, directions[step]);
#endif
/*
* First, just try a kitemap step immediately. If that succeeds,
* we're done.
*/
if ((hc_out = try_step_coords_kitemap(ctx, hc_in, step)) != NULL)
return hc_out;
/*
* Otherwise, try metamap rewrites at successively higher layers
* until one works. Each one will recurse back down to the
* kitemap, as described above.
*/
for (depth = 2;; depth++) {
if ((hc_out = try_step_coords_metamap(
ctx, hc_in, step, depth)) != NULL)
return hc_out;
}
}
/*
* Generate a random set of parameters for a tiling of a given size.
* To do this, we iterate over the whole tiling via first_kite and
* next_kite, and for each kite, calculate its coordinates. But then
* we throw the coordinates away and don't do anything with them!
*
* But the side effect of _calculating_ all those coordinates is that
* we found out how far ctx->prototype needed to be extended, and did
* so, pulling random choices out of our random_state. So after this
* iteration, ctx->prototype contains everything we need to replicate
* the same piece of tiling next time.
*/
void hat_tiling_randomise(struct HatPatchParams *hp, int w, int h,
random_state *rs)
{
HatCoordContext ctx[1];
HatCoords *coords[KE_NKEEP];
KiteEnum s[1];
size_t i;
init_coords_random(ctx, rs);
for (i = 0; i < lenof(coords); i++)
coords[i] = NULL;
first_kite(s, w, h);
coords[s->curr_index] = initial_coords(ctx);
while (next_kite(s)) {
hc_free(coords[s->curr_index]);
coords[s->curr_index] = step_coords(
ctx, coords[s->last_index], s->last_step);
}
hp->ncoords = ctx->prototype->nc - 1;
hp->coords = snewn(hp->ncoords, unsigned char);
for (i = 0; i < hp->ncoords; i++)
hp->coords[i] = ctx->prototype->c[i].index;
hp->final_metatile = tilechars[ctx->prototype->c[hp->ncoords].type];
cleanup_coords(ctx);
for (i = 0; i < lenof(coords); i++)
hc_free(coords[i]);
}
const char *hat_tiling_params_invalid(const struct HatPatchParams *hp)
{
TileType metatile;
size_t i;
if (hp->ncoords < 3)
return "Grid parameters require at least three coordinates";
if (metatile_char_to_enum(hp->final_metatile) < 0)
return "Grid parameters contain an invalid final metatile";
if (hp->coords[0] >= 8)
return "Grid parameters contain an invalid kite index";
metatile = metatile_char_to_enum(hp->final_metatile);
for (i = hp->ncoords - 1; i > 1; i--) {
if (hp->coords[i] >= nchildren[metatile])
return "Grid parameters contain an invalid metatile index";
metatile = children[metatile][hp->coords[i]];
}
if (hp->coords[1] >= hats_in_metatile[metatile])
return "Grid parameters contain an invalid hat index";
return NULL;
}
/*
* For each kite generated by hat_tiling_generate, potentially
* generate an output hat and give it to our caller.
*
* We do this by starting from kite #0 of each hat, and tracing round
* the boundary. If the whole boundary is within the caller's bounding
* region, we return it; if it goes off the edge, we don't.
*
* (Of course, every hat we _do_ want to return will have all its
* kites inside the rectangle, so its kite #0 will certainly be caught
* by this iteration.)
*/
typedef void (*internal_hat_callback_fn)(void *ctx, Kite kite0, HatCoords *hc,
int *coords);
static void maybe_report_hat(int w, int h, Kite kite, HatCoords *hc,
internal_hat_callback_fn cb, void *cbctx)
{
Kite kite0;
Point vertices[14];
size_t i, j;
bool reversed = false;
int coords[28];
/* Only iterate from kite #0 of a hat */
if (hc->c[0].index != 0)
return;
kite0 = kite;
/*
* Identify reflected hats: they are always hat #3 of an H
* metatile. If we find one, reflect the starting kite so that the
* kite_step operations below will go in the other direction.
*/
if (hc->c[2].type == TT_H && hc->c[1].index == 3) {
reversed = true;
Point tmp = kite.left;
kite.left = kite.right;
kite.right = tmp;
}
vertices[0] = kite.centre;
vertices[1] = kite.right;
vertices[2] = kite.outer;
vertices[3] = kite.left;
kite = kite_left(kite); /* now on kite #1 */
kite = kite_forward_right(kite); /* now on kite #2 */
vertices[4] = kite.centre;
kite = kite_right(kite); /* now on kite #3 */
vertices[5] = kite.right;
vertices[6] = kite.outer;
kite = kite_forward_left(kite); /* now on kite #4 */
vertices[7] = kite.left;
vertices[8] = kite.centre;
kite = kite_right(kite); /* now on kite #5 */
kite = kite_right(kite); /* now on kite #6 */
kite = kite_right(kite); /* now on kite #7 */
vertices[9] = kite.right;
vertices[10] = kite.outer;
vertices[11] = kite.left;
kite = kite_left(kite); /* now on kite #6 again */
vertices[12] = kite.outer;
vertices[13] = kite.left;
if (reversed) {
/* For a reversed kite, also reverse the vertex order, so that
* we report every polygon in a consistent orientation */
for (i = 0, j = 13; i < j; i++, j--) {
Point tmp = vertices[i];
vertices[i] = vertices[j];
vertices[j] = tmp;
}
}
/*
* Convert from our internal coordinate system into the orthogonal
* one used in this module's external API. In the same loop, we
* might as well do the bounds check.
*/
for (i = 0; i < 14; i++) {
Point v = vertices[i];
int x = (v.x * 2 + v.y) / 3, y = v.y;
if (x < 0 || x > 4*w || y < 0 || y > 6*h)
return; /* a vertex of this kite is out of bounds */
coords[2*i] = x;
coords[2*i+1] = y;
}
cb(cbctx, kite0, hc, coords);
}
struct internal_ctx {
hat_tile_callback_fn external_cb;
void *external_cbctx;
};
static void report_hat(void *vctx, Kite kite0, HatCoords *hc, int *coords)
{
struct internal_ctx *ctx = (struct internal_ctx *)vctx;
ctx->external_cb(ctx->external_cbctx, 14, coords);
}
/*
* Generate a hat tiling from a previously generated set of parameters.
*/
void hat_tiling_generate(const struct HatPatchParams *hp, int w, int h,
hat_tile_callback_fn cb, void *cbctx)
{
HatCoordContext ctx[1];
HatCoords *coords[KE_NKEEP];
KiteEnum s[1];
size_t i;
struct internal_ctx report_hat_ctx[1];
report_hat_ctx->external_cb = cb;
report_hat_ctx->external_cbctx = cbctx;
init_coords_params(ctx, hp);
for (i = 0; i < lenof(coords); i++)
coords[i] = NULL;
first_kite(s, w, h);
coords[s->curr_index] = initial_coords(ctx);
maybe_report_hat(w, h, *s->curr, coords[s->curr_index],
report_hat, report_hat_ctx);
while (next_kite(s)) {
hc_free(coords[s->curr_index]);
coords[s->curr_index] = step_coords(
ctx, coords[s->last_index], s->last_step);
maybe_report_hat(w, h, *s->curr, coords[s->curr_index],
report_hat, report_hat_ctx);
}
cleanup_coords(ctx);
for (i = 0; i < lenof(coords); i++)
hc_free(coords[i]);
}
#ifdef TEST_HAT
#include <stdarg.h>
static HatCoords *hc_construct_v(TileType type, va_list ap)
{
HatCoords *hc = hc_new();
while (true) {
int index = va_arg(ap, int);
hc_make_space(hc, hc->nc + 1);
hc->c[hc->nc].type = type;
hc->c[hc->nc].index = index;
hc->nc++;
if (index < 0)
return hc;
type = va_arg(ap, TileType);
}
}
static HatCoords *hc_construct(TileType type, ...)
{
HatCoords *hc;
va_list ap;
va_start(ap, type);
hc = hc_construct_v(type, ap);
va_end(ap);
return hc;
}
static bool hc_equal(HatCoords *hc1, HatCoords *hc2)
{
size_t i;
if (hc1->nc != hc2->nc)
return false;
for (i = 0; i < hc1->nc; i++) {
if (hc1->c[i].type != hc2->c[i].type ||
hc1->c[i].index != hc2->c[i].index)
return false;
}
return true;
}
static bool hc_expect(const char *file, int line, HatCoords *hc,
TileType type, ...)
{
bool equal;
va_list ap;
HatCoords *hce;
va_start(ap, type);
hce = hc_construct_v(type, ap);
va_end(ap);
equal = hc_equal(hc, hce);
if (!equal) {
fprintf(stderr, "%s:%d: coordinate mismatch\n", file, line);
debug_coords(" expected: ", hce, "\n");
debug_coords(" actual: ", hc, "\n");
}
hc_free(hce);
return equal;
}
#define EXPECT(hc, ...) do { \
if (!hc_expect(__FILE__, __LINE__, hc, __VA_ARGS__)) \
fails++; \
} while (0)
/*
* For four-colouring the tiling: these tables give a colouring of
* each kitemap, with colour 3 assigned to the reflected tiles in the
* middle of the H, and 0,1,2 chosen arbitrarily.
*/
static const int fourcolours_H[] = {
/* 0 */ 0, 2, 1, 3,
/* 1 */ 1, 0, 2, 3,
/* 2 */ 0, 2, 1, 3,
/* 3 */ 1, -1, -1, -1,
/* 4 */ 1, 2, -1, -1,
/* 5 */ 1, 2, -1, -1,
/* 6 */ 2, 1, -1, -1,
/* 7 */ 0, 1, -1, -1,
/* 8 */ 2, 0, -1, -1,
/* 9 */ 2, 0, -1, -1,
/* 10 */ 0, 1, -1, -1,
/* 11 */ 0, 1, -1, -1,
/* 12 */ 2, 0, -1, -1,
};
static const int fourcolours_T[] = {
/* 0 */ 1, 2, 0, 3,
/* 1 */ 2, 1, -1, -1,
/* 2 */ 0, 1, -1, -1,
/* 3 */ 0, 2, -1, -1,
/* 4 */ 2, 0, -1, -1,
/* 5 */ 0, 1, -1, -1,
/* 6 */ 1, 2, -1, -1,
};
static const int fourcolours_P[] = {
/* 0 */ 2, 1, 0, 3,
/* 1 */ 1, 2, 0, 3,
/* 2 */ 2, 1, -1, -1,
/* 3 */ 0, 2, -1, -1,
/* 4 */ 0, 1, -1, -1,
/* 5 */ 1, 2, -1, -1,
/* 6 */ 2, 0, -1, -1,
/* 7 */ 0, 1, -1, -1,
/* 8 */ 1, 0, -1, -1,
/* 9 */ 2, 1, -1, -1,
/* 10 */ 0, 2, -1, -1,
};
static const int fourcolours_F[] = {
/* 0 */ 2, 0, 1, 3,
/* 1 */ 0, 2, 1, 3,
/* 2 */ 1, 2, -1, -1,
/* 3 */ 1, 0, -1, -1,
/* 4 */ 0, 2, -1, -1,
/* 5 */ 2, 1, -1, -1,
/* 6 */ 2, 0, -1, -1,
/* 7 */ 0, 1, -1, -1,
/* 8 */ 0, 1, -1, -1,
/* 9 */ 2, 0, -1, -1,
/* 10 */ 1, 2, -1, -1,
};
static const int *const fourcolours[] = {
fourcolours_H, fourcolours_T, fourcolours_P, fourcolours_F,
};
/*
* Structure that describes how the colours in the above maps are
* translated to output colours. This will vary with each kitemap our
* coordinates pass through, in order to maintain consistency.
*/
typedef struct FourColourMap {
unsigned char map[4];
} FourColourMap;
/*
* Make an initial FourColourMap by choosing the initial permutation
* of the three 'normal' hat colours randomly.
*/
static inline FourColourMap fourcolourmap_initial(random_state *rs)
{
FourColourMap f;
unsigned i;
/* Start with the identity mapping */
for (i = 0; i < 4; i++)
f.map[i] = i;
/* Randomly permute colours 0,1,2, leaving 3 as the distinguished
* colour for reflected hats */
shuffle(f.map, 3, sizeof(f.map[0]), rs);
return f;
}
static inline FourColourMap fourcolourmap_update(
FourColourMap prevm, HatCoords *prevc, HatCoords *currc, KiteStep step,
HatCoordContext *ctx)
{
size_t i, m1, m2;
const int *f1, *f2;
unsigned sum;
int missing;
FourColourMap newm;
HatCoords *prev2c;
/*
* If prevc and currc are in the same kitemap anyway, that's the
* easy case: the colour map for the new kitemap is the same as
* for the old one, because they're the same kitemap.
*/
ensure_coords(ctx, prevc, currc->nc);
ensure_coords(ctx, currc, prevc->nc);
for (i = 3; i < prevc->nc; i++)
if (currc->c[i].index != prevc->c[i].index)
goto mismatch;
return prevm;
mismatch:
/*
* The step_coords algorithm guarantees that the _new_ coordinate
* currc is expected to be in a kitemap containing both this kite
* and the previous one (because it first transformed the previous
* coordinate until it _could_ take a step within the same
* kitemap, and then did).
*
* So if we reverse the last step we took, we should get a second
* HatCoords describing the same kite as prevc but showing its
* position in the _new_ kitemap. This lets us figure out a pair
* of corresponding metatile indices within the old and new
* kitemaps (by looking at which metatile prevc and prev2c claim
* to be in).
*
* That metatile will also always be a P or an F (because all
* metatiles overlapping the next kitemap are of those types),
* which means it will have two hats in it. And those hats will be
* adjacent, so differently coloured. Hence, we have enough
* information to decide how two of the new kitemap's three normal
* colours map to the colours we were using in the old kitemap -
* and then the third is determined by process of elimination.
*/
prev2c = step_coords(
ctx, currc, (step == KS_LEFT ? KS_RIGHT :
step == KS_RIGHT ? KS_LEFT :
step == KS_F_LEFT ? KS_F_RIGHT : KS_F_LEFT));
/* Metatile indices within the old and new kitemaps */
m1 = prevc->c[2].index;
m2 = prev2c->c[2].index;
/* The colourings of those metatiles' hats in our fixed fourcolours[] */
f1 = fourcolours[prevc->c[3].type] + 4*m1;
f2 = fourcolours[prev2c->c[3].type] + 4*m2;
/*
* Start making our new output map, filling in all three normal
* colours to 255 = "don't know yet".
*/
newm.map[3] = 3;
newm.map[0] = newm.map[1] = newm.map[2] = 255;
/*
* Iterate over the tile colourings in fourcolours[] for these
* metatiles, matching up our mappings.
*/
for (i = 0; i < 4; i++) {
/* They should be the same metatile, so have same number of hats! */
assert((f1[i] == -1) == (f2[i] == -1));
if (f1[i] != 255)
newm.map[f2[i]] = prevm.map[f1[i]];
}
/*
* We expect to have filled in exactly two of the three normal
* colours. Find the missing index, and fill in its colour by
* arithmetic (using the fact that the three colours add up to 3).
*/
sum = 0;
missing = -1;
for (i = 0; i < 3; i++) {
if (newm.map[i] == 255) {
assert(missing == -1); /* shouldn't have two missing colours */
missing = i;
} else {
sum += newm.map[i];
}
}
assert(missing != -1);
assert(0 < sum && sum <= 3);
newm.map[missing] = 3 - sum;
return newm;
}
static bool unit_tests(void)
{
int fails = 0;
HatCoordContext ctx[1];
HatCoords *hc_in, *hc_out;
ctx->rs = NULL;
ctx->prototype = hc_construct(TT_KITE, 0, TT_HAT, 0, TT_H, -1);
/* Simple steps within a hat */
hc_in = hc_construct(TT_KITE, 6, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_out = step_coords(ctx, hc_in, KS_LEFT);
EXPECT(hc_out, TT_KITE, 5, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_free(hc_in);
hc_free(hc_out);
hc_in = hc_construct(TT_KITE, 6, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_out = step_coords(ctx, hc_in, KS_RIGHT);
EXPECT(hc_out, TT_KITE, 7, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_free(hc_in);
hc_free(hc_out);
hc_in = hc_construct(TT_KITE, 5, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_out = step_coords(ctx, hc_in, KS_F_LEFT);
EXPECT(hc_out, TT_KITE, 2, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_free(hc_in);
hc_free(hc_out);
hc_in = hc_construct(TT_KITE, 5, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_out = step_coords(ctx, hc_in, KS_F_RIGHT);
EXPECT(hc_out, TT_KITE, 1, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_free(hc_in);
hc_free(hc_out);
/* Step between hats in the same kitemap, which can change the
* metatile type at layer 2 */
hc_in = hc_construct(TT_KITE, 6, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_out = step_coords(ctx, hc_in, KS_F_LEFT);
EXPECT(hc_out, TT_KITE, 3, TT_HAT, 0, TT_H, 0, TT_H, -1);
hc_free(hc_in);
hc_free(hc_out);
hc_in = hc_construct(TT_KITE, 7, TT_HAT, 2, TT_H, 1, TT_H, -1);
hc_out = step_coords(ctx, hc_in, KS_F_RIGHT);
EXPECT(hc_out, TT_KITE, 4, TT_HAT, 0, TT_T, 3, TT_H, -1);
hc_free(hc_in);
hc_free(hc_out);
/* Step off the edge of one kitemap, necessitating a metamap
* rewrite of layers 2,3 to get into a different kitemap where
* that step can be made */
hc_in = hc_construct(TT_KITE, 6, TT_HAT, 0, TT_P, 2, TT_P, 3, TT_P, -1);
hc_out = step_coords(ctx, hc_in, KS_F_RIGHT);
/* Working:
* kite 6 . hat 0 . P 2 . P 3 . P ?
* -> kite 6 . hat 0 . P 6 . H 0 . P ? (P metamap says 2.3 = 6.0)
*/
EXPECT(hc_out, TT_KITE, 7, TT_HAT, 1, TT_H, 1, TT_H, 0, TT_P, -1);
hc_free(hc_in);
hc_free(hc_out);
cleanup_coords(ctx);
return fails == 0;
}
typedef struct pspoint {
float x, y;
} pspoint;
typedef struct psbbox {
bool started;
pspoint bl, tr;
} psbbox;
static inline void psbbox_add(psbbox *bbox, pspoint p)
{
if (!bbox->started || bbox->bl.x > p.x)
bbox->bl.x = p.x;
if (!bbox->started || bbox->tr.x < p.x)
bbox->tr.x = p.x;
if (!bbox->started || bbox->bl.y > p.y)
bbox->bl.y = p.y;
if (!bbox->started || bbox->tr.y < p.y)
bbox->tr.y = p.y;
bbox->started = true;
}
typedef enum OutFmt { OF_POSTSCRIPT, OF_PYTHON } OutFmt;
typedef enum ColourMode { CM_SEMANTIC, CM_FOURCOLOUR } ColourMode;
typedef struct drawctx {
OutFmt outfmt;
ColourMode colourmode;
psbbox *bbox;
KiteEnum *kiteenum;
FourColourMap fourcolourmap[KE_NKEEP];
} drawctx;
static void bbox_add_hat(void *vctx, Kite kite0, HatCoords *hc, int *coords)
{
drawctx *ctx = (drawctx *)vctx;
pspoint p;
size_t i;
for (i = 0; i < 14; i++) {
p.x = coords[2*i] * 1.5;
p.y = coords[2*i+1] * sqrt(0.75);
psbbox_add(ctx->bbox, p);
}
}
static void header(drawctx *ctx)
{
switch (ctx->outfmt) {
case OF_POSTSCRIPT: {
float xext = ctx->bbox->tr.x - ctx->bbox->bl.x;
float yext = ctx->bbox->tr.y - ctx->bbox->bl.y;
float ext = (xext > yext ? xext : yext);
float scale = 500 / ext;
float ox = 287 - scale * (ctx->bbox->bl.x + ctx->bbox->tr.x) / 2;
float oy = 421 - scale * (ctx->bbox->bl.y + ctx->bbox->tr.y) / 2;
printf("%%!PS-Adobe-2.0\n%%%%Creator: hat-test from Simon Tatham's "
"Portable Puzzle Collection\n%%%%Pages: 1\n"
"%%%%BoundingBox: %f %f %f %f\n"
"%%%%EndComments\n%%%%Page: 1 1\n",
ox + scale * ctx->bbox->bl.x - 20,
oy + scale * ctx->bbox->bl.y - 20,
ox + scale * ctx->bbox->tr.x + 20,
oy + scale * ctx->bbox->tr.y + 20);
printf("%f %f translate %f dup scale\n", ox, oy, scale);
printf("%f setlinewidth\n", scale * 0.03);
printf("0 setgray 1 setlinejoin 1 setlinecap\n");
break;
}
default:
break;
}
}
static void draw_hat(void *vctx, Kite kite0, HatCoords *hc, int *coords)
{
drawctx *ctx = (drawctx *)vctx;
pspoint p;
size_t i;
int orientation;
/*
* Determine an index for the hat's orientation, based on the axis
* of symmetry of its kite #0.
*/
{
int dx = kite0.outer.x - kite0.centre.x;
int dy = kite0.outer.y - kite0.centre.y;
orientation = 0;
while (dx < 0 || dy < 0) {
int newdx = dx + dy;
int newdy = -dx;
dx = newdx;
dy = newdy;
orientation++;
assert(orientation < 6);
}
}
switch (ctx->outfmt) {
case OF_POSTSCRIPT: {
const char *colour;
printf("newpath");
for (i = 0; i < 14; i++) {
p.x = coords[2*i] * 1.5;
p.y = coords[2*i+1] * sqrt(0.75);
printf(" %f %f %s", p.x, p.y, i ? "lineto" : "moveto");
}
printf(" closepath gsave");
switch (ctx->colourmode) {
case CM_SEMANTIC:
if (hc->c[2].type == TT_H) {
colour = (hc->c[1].index == 3 ? "0 0.5 0.8 setrgbcolor" :
"0.6 0.8 1 setrgbcolor");
} else if (hc->c[2].type == TT_F) {
colour = "0.7 setgray";
} else {
colour = "1 setgray";
}
break;
default /* case CM_FOURCOLOUR */: {
/*
* Determine the colour of this tile by translating the
* fixed colour from fourcolours[] through our current
* FourColourMap.
*/
FourColourMap f = ctx->fourcolourmap[ctx->kiteenum->curr_index];
const int *m = fourcolours[hc->c[3].type];
static const char *const colours[] = {
"1 0.7 0.7 setrgbcolor",
"1 1 0.7 setrgbcolor",
"0.7 1 0.7 setrgbcolor",
"0.6 0.6 1 setrgbcolor",
};
colour = colours[f.map[m[hc->c[2].index * 4 + hc->c[1].index]]];
break;
}
}
printf(" %s fill grestore", colour);
printf(" stroke\n");
break;
}
case OF_PYTHON: {
printf("hat('%c', %d, %d, [", "HTPF"[hc->c[2].type], hc->c[1].index,
orientation);
for (i = 0; i < 14; i++)
printf("%s(%d,%d)", i ? ", " : "", coords[2*i], coords[2*i+1]);
printf("])\n");
break;
}
}
}
static void trailer(drawctx *dctx)
{
switch (dctx->outfmt) {
case OF_POSTSCRIPT: {
printf("showpage\n");
printf("%%%%Trailer\n");
printf("%%%%EOF\n");
break;
}
default:
break;
}
}
int main(int argc, char **argv)
{
psbbox bbox[1];
KiteEnum s[1];
HatCoordContext ctx[1];
HatCoords *coords[KE_NKEEP];
random_state *rs;
const char *random_seed = "12345";
int w = 10, h = 10;
int argpos = 0;
size_t i;
drawctx dctx[1];
dctx->outfmt = OF_POSTSCRIPT;
dctx->colourmode = CM_SEMANTIC;
dctx->kiteenum = s;
while (--argc > 0) {
const char *arg = *++argv;
if (!strcmp(arg, "--help")) {
printf(" usage: hat-test [options] [<width>] [<height>]\n"
"options: --python write a Python function call per hat\n"
" --seed=STR vary the starting random seed\n"
" also: hat-test --test\n");
return 0;
} else if (!strcmp(arg, "--test")) {
return unit_tests() ? 0 : 1;
} else if (!strcmp(arg, "--python")) {
dctx->outfmt = OF_PYTHON;
} else if (!strcmp(arg, "--fourcolour")) {
dctx->colourmode = CM_FOURCOLOUR;
} else if (!strncmp(arg, "--seed=", 7)) {
random_seed = arg+7;
} else if (arg[0] == '-') {
fprintf(stderr, "unrecognised option '%s'\n", arg);
return 1;
} else {
switch (argpos++) {
case 0:
w = atoi(arg);
break;
case 1:
h = atoi(arg);
break;
default:
fprintf(stderr, "unexpected extra argument '%s'\n", arg);
return 1;
}
}
}
for (i = 0; i < lenof(coords); i++)
coords[i] = NULL;
rs = random_new(random_seed, strlen(random_seed));
init_coords_random(ctx, rs);
bbox->started = false;
dctx->bbox = bbox;
first_kite(s, w, h);
coords[s->curr_index] = initial_coords(ctx);
maybe_report_hat(w, h, *s->curr, coords[s->curr_index],
bbox_add_hat, dctx);
while (next_kite(s)) {
hc_free(coords[s->curr_index]);
coords[s->curr_index] = step_coords(
ctx, coords[s->last_index], s->last_step);
maybe_report_hat(w, h, *s->curr, coords[s->curr_index],
bbox_add_hat, dctx);
}
for (i = 0; i < lenof(coords); i++) {
hc_free(coords[i]);
coords[i] = NULL;
}
header(dctx);
first_kite(s, w, h);
coords[s->curr_index] = initial_coords(ctx);
dctx->fourcolourmap[s->curr_index] = fourcolourmap_initial(rs);
maybe_report_hat(w, h, *s->curr, coords[s->curr_index],
draw_hat, dctx);
while (next_kite(s)) {
hc_free(coords[s->curr_index]);
coords[s->curr_index] = step_coords(
ctx, coords[s->last_index], s->last_step);
dctx->fourcolourmap[s->curr_index] = fourcolourmap_update(
dctx->fourcolourmap[s->last_index], coords[s->last_index],
coords[s->curr_index], s->last_step, ctx);
maybe_report_hat(w, h, *s->curr, coords[s->curr_index],
draw_hat, dctx);
}
for (i = 0; i < lenof(coords); i++) {
hc_free(coords[i]);
coords[i] = NULL;
}
trailer(dctx);
cleanup_coords(ctx);
return 0;
}
#endif